package com.fishercoder.solutions;

/**
 * 552. Student Attendance Record II
 *
 * Given a positive integer n, return the number of all possible attendance records with length n,
 * which will be regarded as rewardable. The answer may be very large, return it after mod 109 + 7.

 A student attendance record is a string that only contains the following three characters:

 'A' : Absent.
 'L' : Late.
 'P' : Present.

 A record is regarded as rewardable if it doesn't contain more than one 'A' (absent) or more than two continuous 'L' (late).

 Example 1:

 Input: n = 2
 Output: 8

 Explanation:
 There are 8 records with length 2 will be regarded as rewardable:
 "PP" , "AP", "PA", "LP", "PL", "AL", "LA", "LL"
 Only "AA" won't be regarded as rewardable owing to more than one absent times.

 Note: The value of n won't exceed 100,000.
 */
public class _552 {

    public static class Solution1 {
        /**
         * credit: https://discuss.leetcode.com/topic/86526/improving-the-runtime-from-o-n-to-o-log-n
         */
        public int checkRecord(int n) {
            final int MOD = 1000000007;
            int[][][] f = new int[n + 1][2][3];

            f[0] = new int[][]{{1, 1, 1}, {1, 1, 1}};
            for (int i = 1; i <= n; i++) {
                for (int j = 0; j < 2; j++) {
                    for (int k = 0; k < 3; k++) {
                        int val = f[i - 1][j][2]; // ...P
                        if (j > 0) {
                            val = (val + f[i - 1][j - 1][2]) % MOD; // ...A
                        }
                        if (k > 0) {
                            val = (val + f[i - 1][j][k - 1]) % MOD; // ...L
                        }
                        f[i][j][k] = val;
                    }
                }
            }
            return f[n][1][2];
        }
    }

}