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徐长贺/Leetcode

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_662.java 3.09 KB
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Fisher Coder 提交于 6年前 . refactor 662
package com.fishercoder.solutions;
import com.fishercoder.common.classes.TreeNode;
import java.util.AbstractMap;
import java.util.ArrayList;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
import java.util.Queue;
/**
* 662. Maximum Width of Binary Tree
*
* Given a binary tree, write a function to get the maximum width of the given tree.
* The width of a tree is the maximum width among all levels.
* The binary tree has the same structure as a full binary tree, but some nodes are null.
* The width of one level is defined as the length between the end-nodes
* (the leftmost and right most non-null nodes in the level,
* where the null nodes between the end-nodes are also counted into the length calculation.
Example 1:
Input:
1
/ \
3 2
/ \ \
5 3 9
Output: 4
Explanation: The maximum width existing in the third level with the length 4 (5,3,null,9).
Example 2:
Input:
1
/
3
/ \
5 3
Output: 2
Explanation: The maximum width existing in the third level with the length 2 (5,3).
Example 3:
Input:
1
/ \
3 2
/
5
Output: 2
Explanation: The maximum width existing in the second level with the length 2 (3,2).
Example 4:
Input:
1
/ \
3 2
/ \
5 9
/ \
6 7
Output: 8
Explanation:The maximum width existing in the fourth level with the length 8 (6,null,null,null,null,null,null,7).
Note: Answer will in the range of 32-bit signed integer.
*/
public class _662 {
public static class Solution1 {
/**
* Use a map to store the node to value map,
* we use root as index 1, then its left child is 2*i-1 and right child is 2*i
*/
public int widthOfBinaryTree(TreeNode root) {
if (root == null) {
return 0;
}
Queue<Map.Entry<TreeNode, Integer>> queue = new LinkedList<>();
queue.offer(new AbstractMap.SimpleEntry<>(root, 1));
int max = 1;
while (!queue.isEmpty()) {
int size = queue.size();
List<Map.Entry<TreeNode, Integer>> list = new ArrayList<>();
for (int i = 0; i < size; i++) {
Map.Entry<TreeNode, Integer> curr = queue.poll();
if (curr.getKey().left != null) {
Map.Entry<TreeNode, Integer> newEntry = new AbstractMap.SimpleEntry<>(curr.getKey().left, curr.getValue() * 2 - 1);
queue.offer(newEntry);
list.add(newEntry);
}
if (curr.getKey().right != null) {
Map.Entry<TreeNode, Integer> newEntry = new AbstractMap.SimpleEntry<>(curr.getKey().right, curr.getValue() * 2);
queue.offer(newEntry);
list.add(newEntry);
}
}
if (list.size() > 1) {
max = Math.max(list.get(list.size() - 1).getValue() - list.get(0).getValue() + 1, max);
}
}
return max;
}
}
}
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