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package com.fishercoder.solutions;
import com.fishercoder.common.classes.TreeNode;
/**
* 814. Binary Tree Pruning
*
* We are given the head node root of a binary tree, where additionally every node's value is either a 0 or a 1.
* Return the same tree where every subtree (of the given tree) not containing a 1 has been removed.
* (Recall that the subtree of a node X is X, plus every node that is a descendant of X.)
*
* Example 1:
* Input: [1,null,0,0,1]
* Output: [1,null,0,null,1]
* Explanation:
* Only the red nodes satisfy the property "every subtree not containing a 1".
* The diagram on the right represents the answer.
* 1 1
* \ \
* 0 ----> 0
* / \ \
* 0 1 1
*
*
* Example 2:
* Input: [1,0,1,0,0,0,1]
* Output: [1,null,1,null,1]
* 1 1
* / \ \
* 0 1 ----> 1
* / \ / \ \
* 0 0 0 1 1
*
*
* Example 3:
* Input: [1,1,0,1,1,0,1,0]
* Output: [1,1,0,1,1,null,1]
* 1 1
* / \ / \
* 1 0 -----> 1 0
* / \ / \ / \ \
* 1 1 0 1 1 1 1
* /
* 0
*
*
* Note:
*
* The binary tree will have at most 100 nodes.
* The value of each node will only be 0 or 1.*/
public class _814 {
public static class Solution1 {
/**credit: https://leetcode.com/problems/binary-tree-pruning/discuss/122730/C%2B%2BJavaPython-Self-Explaining-Solution-and-2-lines*/
public TreeNode pruneTree(TreeNode root) {
if (root == null) {
return root;
}
root.left = pruneTree(root.left);
root.right = pruneTree(root.right);
if (root.left == null && root.right == null && root.val == 0) {
return null;
}
return root;
}
}
}
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