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徐长贺/Leetcode

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_989.java 1.98 KB
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Fisher Coder 提交于 2019-02-16 01:35 +08:00 . add 989
package com.fishercoder.solutions;
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
/**
* 989. Add to Array-Form of Integer
*
* For a non-negative integer X, the array-form of X is an array of its digits in left to right order. For example, if X = 1231, then the array form is [1,2,3,1].
*
* Given the array-form A of a non-negative integer X, return the array-form of the integer X+K.
*
* Example 1:
*
* Input: A = [1,2,0,0], K = 34
* Output: [1,2,3,4]
* Explanation: 1200 + 34 = 1234
* Example 2:
*
* Input: A = [2,7,4], K = 181
* Output: [4,5,5]
* Explanation: 274 + 181 = 455
* Example 3:
*
* Input: A = [2,1,5], K = 806
* Output: [1,0,2,1]
* Explanation: 215 + 806 = 1021
* Example 4:
*
* Input: A = [9,9,9,9,9,9,9,9,9,9], K = 1
* Output: [1,0,0,0,0,0,0,0,0,0,0]
* Explanation: 9999999999 + 1 = 10000000000
*
* Note:
*
* 1 <= A.length <= 10000
* 0 <= A[i] <= 9
* 0 <= K <= 10000
* If A.length > 1, then A[0] != 0
*/
public class _989 {
public static class Solution1 {
public List<Integer> addToArrayForm(int[] A, int K) {
List<Integer> kDigitsReversed = new ArrayList<>();
int divisor = 10;
while (K != 0) {
kDigitsReversed.add(K % divisor);
K /= 10;
}
List<Integer> result = new ArrayList<>();
int prevFlow = 0;
for (int i = A.length - 1, j = 0; i >= 0 || j < kDigitsReversed.size(); i --, j++) {
int sum;
if (i >= 0 && j < kDigitsReversed.size()) {
sum = A[i] + kDigitsReversed.get(j);
} else if (i >= 0) {
sum = A[i];
} else {
sum = kDigitsReversed.get(j);
}
int flow = 0;
if (prevFlow != 0) {
sum += prevFlow;
}
if (sum > 9) {
flow = 1;
}
sum %= 10;
prevFlow = flow;
result.add(sum);
}
if (prevFlow != 0) {
result.add(prevFlow);
}
Collections.reverse(result);
return result;
}
}
}
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