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<body>
<h1 id="-">第三章作业</h1>
<h2 id="1-">1.填空题</h2>
<ul>
<li>1.1 不能使用类对象的指针取对象的（    ）和 （       ）的地址。</li><li>1.2 构造函数是和(     )同名的函数，析构函数不允许有(      )，一个类有(       )个析构函数。</li><li>1.3 已知一个类的名字为fun，则其复制构造函数的原型可声明为(     )和(     )两种形式。</li></ul>
<h2 id="2-">2.单项选择题</h2>
<h3 id="2-1-c-">2.1 能提供封装的c++的下列关键字是(   )</h3>
<pre><code>A.while
B.union
C.class
D.for
</code></pre><hr>
<h3 id="2-2-">2.2 下列不是面向对象的特点的是(    )</h3>
<pre><code>A.多态性
B.抽象性和封装性
C.多线程和多任务
D.继承性
</code></pre><hr>
<h3 id="2-3-a-">2.3 下列选项中，对类A的析构函数的正确定义是(    )</h3>
<pre><code>A.~A::A(void)
B.void ~A::A(参数)
C.~A::A(参数)
D.void ~A::A()
</code></pre><hr>
<h3 id="2-4-">2.4 下面有关构造函数的不正确说法是(   )</h3>
<pre><code>A.构造函数可以用来实现所有成员变量的初始化
B.构造函数不是类的成员函数
C.当生成类的实例时，自动调用构造函数进行初始化
D.构造函数用来分配对象所需的内存
</code></pre><hr>
<h3 id="2-5-">2.5 有关析构函数的不正确的说法是（   ）</h3>
<pre><code>A. 析构函数在对象生存期结束时被调用
B. 析构函数不得指定参数
C. 定义析构函数时，可以指定返回类型为void
D. 析构函数名与类名相同
</code></pre><hr>
<h3 id="2-6-">2.6 下面有关类说法错误的是(    )</h3>
<pre><code>A. 一个类可以有多个构造函数
B. 一个类只能有一个析构函数
C. 可以给析构函数指定参数
D. 一个类中可以说明具有类类型的数据成员
</code></pre><hr>
<h3 id="2-7-new-">2.7 下面有关构造函数和new 运算符关系的正确说法是(     )</h3>
<pre><code>A. new 运算符不调用构造函数
B. 构造函数一定调用new 运算符
C. 当生成类的实例时，先调用new运算符，然后调用构造函数进行初始化
D. 当用new运算符动态生成类的对象时，new运算符也自动调用构造函数
</code></pre><hr>
<h2 id="3-">3.改错题</h2>
<h3 id="3-1-">3.1 找出以下类定义的错误，并说明错在何处</h3>
<pre><code class="lang-c++">class base{
    int *p;
public:
    base(int a){p = &amp;a};
    int Getx(){return m;}
    ~base(){delete p}
};
</code></pre>
<hr>
<h3 id="3-2-">3.2 找到程序中的错误并改正之</h3>
<pre><code class="lang-c++">#include &lt;iostream&gt;
class Point{
    int x;
public:
    void init(int a){Setx(a);}
    int Getx(){return x;}
    int Setx(int a){x = a;}
};
void main(){
    A.init(24,56);
    cout&lt;&lt;&quot;A.x = &quot;&lt;&lt;A.Getx()&lt;&lt;endl;
}
</code></pre>
<h2 id="4-">4.完成程序题</h2>
<h3 id="4-1-">4.1 下面是一个类的测试程序，设计出能使用如下测试程序的类:</h3>
<pre><code class="lang-c++">void main()
{
    base a;
    a.init(68,55);
    a.print();
}
</code></pre>
<h3 id="4-2-">4.2 完成下面类中的成员函数的定义</h3>
<pre><code class="lang-c++">class Point{
private:
    int m, n;
public:
    Point(int, int);
    Point(Point&amp;);
};
Point::Point(         )
{
    m = a;
      = b;
}
Point::Point(        )
{
    m =
    n = t.n;
}
</code></pre>
<hr>
<h2 id="5-">5.程序分析题</h2>
<h3 id="5-1-">5.1 给出下列程序的输出结果</h3>
<pre><code class="lang-c++">#include &lt;iostream.h&gt;
class base{
private:
    int a, b;
public:
    ~base(){cout&lt;&lt;&quot;Destroy...&quot;&lt;&lt;a&lt;&lt;&quot;,&quot;&lt;&lt;b&lt;&lt;endl;}
    base(int a,int b):b(b),a(a)
    {cout&lt;&lt;&quot;初始化...&quot;&lt;&lt;a&lt;&lt;&quot;，&quot;&lt;&lt;b&lt;&lt;endl;}
};
</code></pre>
<h3 id="5-2-">5.2 分析下面程序的输出结果</h3>
<pre><code class="lang-c++">class base{
private:
    int x;
public:
    void setx(int a){x = a;}
    int getx(){return x;}
};
void main()
{
    int *p;
    base a;
    a.setx(55);
    p = new int(a.getx());
    cout&lt;&lt;*p;
}
</code></pre>
<hr>
<h2 id="6-">6.编程题</h2>
<h3 id="6-1-point-point-4-">6.1 设计一个点类Point，再设计一个矩形类，矩形类使用Point类的两个坐标点作为矩形的对角顶点，并且可以输出4个坐标值和面积。使用测试程序验证程序。</h3>
<hr>
<h3 id="6-2-">6.2 使用内联函数设计一个类，用来表示直角坐标系中的任意一条直线并输出它的属性。</h3>
<hr>
<h2 id="7-">7.作图题</h2>
<h3 id="7-1-line-rectangle-">7.1 假设不涉及操作，已经定义了类Line，使用继承的方法组成Rectangle类。</h3>
<h3 id="7-2-line-rectangle-">7.2 假设不涉及操作，已经定义了类Line，使用聚合的方法组成Rectangle类。</h3>
<hr>

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