# If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9.
# The sum of these multiples is 23.
# Find the sum of all the multiples of 3 or 5 below 1000.

class Multiples(object):
    def Multiples_three_and_five(self, num):
        num_list = []
        for i in range(1, num):
            if i % 3 == 0:
                num_list.append(i)
            elif i % 5 == 0:
                num_list.append(i)
        return num_list

    def Sum_list(self, Num_list):
        sum = 0
        for i in Num_list:
            sum = i + sum
        print 'sum of the list is %d' % (sum)
        return sum

    def Multiple_list(self, Num_list):
        result = 1
        for i in Num_list:
            result = i * result
        print 'multiple of the list is %d' % result
        return result


# refactor code 2016/6/21
class Multiples_refactor(object):
    def Multiples_three_and_five(self, num):
        return [x for x in range(1, num) if x % 3 == 0 or x % 5 == 0]

    def Sum_list(self, Num_list):
        return sum(Num_list)

    def Multiple_list(self, Num_list):
        return reduce(lambda x, y: x * y, Num_list)


if __name__ == '__main__':
    num = 100
    Myobject = Multiples()
    Num_list = Myobject.Multiples_three_and_five(num)
    print Num_list
    print Myobject.Sum_list(Num_list)

    print "split line, refactor"
    num = 100
    Myobject = Multiples_refactor()
    Num_list = Myobject.Multiples_three_and_five(num)
    print Num_list
    print Myobject.Sum_list(Num_list)