代码拉取完成,页面将自动刷新
# Time: O(1)
# Space: O(1)
# There are n bulbs that are initially off.
# You first turn on all the bulbs. Then,
# you turn off every second bulb. On the
# third round, you toggle every third bulb
# (turning on if it's off or turning off if
# it's on). For the nth round, you only
# toggle the last bulb. Find how many bulbs
# are on after n rounds.
#
# Example:
#
# Given n = 3.
#
# At first, the three bulbs are [off, off, off].
# After first round, the three bulbs are [on, on, on].
# After second round, the three bulbs are [on, off, on].
# After third round, the three bulbs are [on, off, off].
#
# So you should return 1, because there is
# only one bulb is on.
class Solution(object):
def bulbSwitch(self, n):
"""
type n: int
rtype: int
"""
# The number of full squares.
return int(math.sqrt(n))
此处可能存在不合适展示的内容,页面不予展示。您可通过相关编辑功能自查并修改。
如您确认内容无涉及 不当用语 / 纯广告导流 / 暴力 / 低俗色情 / 侵权 / 盗版 / 虚假 / 无价值内容或违法国家有关法律法规的内容,可点击提交进行申诉,我们将尽快为您处理。