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find-the-smallest-divisor-given-a-threshold.cpp 783 Bytes
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// Time: O(logn)
// Space: O(1)
class Solution {
public:
int smallestDivisor(vector<int>& nums, int threshold) {
int left = 1, right = *max_element(nums.cbegin(), nums.cend());
while (left <= right) {
const auto& mid = left + (right - left) / 2;
if (check(nums, mid, threshold)) {
right = mid - 1;
} else {
left = mid + 1;
}
}
return left;
}
private:
bool check(const vector<int>& nums, int x, int threshold) {
return accumulate(nums.cbegin(), nums.cend(), 0,
[&x](const auto& a, const auto& b) {
return a + (b - 1) / x + 1;
})
<= threshold;
}
};
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