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linked-list-random-node.py 766 Bytes
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Allen Liu 提交于 7年前 . add complexity
# Time: O(n)
# Space: O(1)
from random import randint
class Solution(object):
def __init__(self, head):
"""
@param head The linked list's head. Note that the head is guanranteed to be not null, so it contains at least one node.
:type head: ListNode
"""
self.__head = head
# Proof of Reservoir Sampling:
# https://discuss.leetcode.com/topic/53753/brief-explanation-for-reservoir-sampling
def getRandom(self):
"""
Returns a random node's value.
:rtype: int
"""
reservoir = -1
curr, n = self.__head, 0
while curr:
reservoir = curr.val if randint(1, n+1) == 1 else reservoir
curr, n = curr.next, n+1
return reservoir
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