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minimum-number-of-refueling-stops.py 736 Bytes
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Allen Liu 提交于 7年前 . add complexity
# Time: O(nlogn)
# Space: O(n)
import heapq
class Solution(object):
def minRefuelStops(self, target, startFuel, stations):
"""
:type target: int
:type startFuel: int
:type stations: List[List[int]]
:rtype: int
"""
max_heap = []
stations.append((target, float("inf")))
result = prev = 0
for location, capacity in stations:
startFuel -= location - prev
while max_heap and startFuel < 0:
startFuel += -heapq.heappop(max_heap)
result += 1
if startFuel < 0:
return -1
heapq.heappush(max_heap, -capacity)
prev = location
return result
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