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require a compiled es6 module and handle exports.default.
$ npm i require-esmodule
// foo.js
Object.defineProperty(exports, '__esModule', {value: true})
exports.default = {
foo: 'default-foo'
}
exports.foo = 'foo'
// bar.js
module.exports = {
default: {
bar: 'default-bar'
},
bar: 'bar'
}
// baz.js
module.exports = null
// qux.js
const {
requireModule,
getExports
} = require('require-esmodule')
console.log(requireModule('/path/to/foo').foo) // 'default-foo'
console.log(requireModule('/path/to/foo', false).foo) // 'foo'
console.log(requireModule('/path/to/bar').bar) // 'bar'
// bar.js is not a es6 module
console.log(requireModule('/path/to/baz')) // null
string ABSOLUTE path of the moduleboolean=true whether should require export default. Defaults to true.Returns any the module exports
requireDefault as falseconst foo = requireModule('./foo', false)
is equivalent to:
import * as foo from './foo'
while
const foo = requireModule('./foo')
is equivalent to:
import foo from './foo'
The purpose of require-esmodule is to detect and make it easier to get the default exports of es modules, so the default value of requireDefault is set to true
Detect and get the real exports from the return value of require(id)
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